1.4 Lösning 5c
Från Mathonline
\( {3 \over a\,-\,2} - {a\,+\,7 \over 6\,-\,3\,a} \; = \; {3 \over a\,-\,2} - {a\,+\,7 \over 3\,(2\,-\,a)} \; = \; {3 \over a\,-\,2} - {a\,+\,7 \over -3\,(a\,-\,2)} \; = \)
\( = {3 \over a\,-\,2} + {a\,+\,7 \over 3\,(a\,-\,2)} = {3 \cdot 3 \over 3\,(a\,-\,2)} + {a\,+\,7 \over 3\,(a\,-\,2)} = {9\,+\,a\,+\,7 \over 3\,(a\,-\,2)} = {a\,+\,16 \over 3\,(a\,-\,2)} \)
