1.4 Lösning 6a
Från Mathonline
\( {3\,(y\,-\,3) \over 8\,y}\cdot{24\,y \over y\,-\,3} = {3\,(y\,-\,3)\,\cdot\,24\,y \over 8\,y\,\cdot\,(y\,-\,3)} = {3\,\cdot\,24\,y \over 8\,y} = {3\,\cdot\,24 \over 8} = {3\,\cdot\,3\,\cdot\,8 \over 8} = \) \( {\color{White} l} 9 \)
