1.5 Lösning 4b
Från Mathonline
\( {\sqrt{{4^{40} \over 4} \; / \; 4^{38}}} = {\sqrt{4^{39} \; / \; 4^{38}}} = {\sqrt{4^{39-38}}} = \sqrt{4} = 2 \)
\( {\sqrt{{4^{40} \over 4} \; / \; 4^{38}}} = {\sqrt{4^{39} \; / \; 4^{38}}} = {\sqrt{4^{39-38}}} = \sqrt{4} = 2 \)