2.3a Lösning 4b
Från Mathonline
\[ \lim_{x \to \infty}\,{12 \over x\,-\,3} \, = \, 12 \cdot \lim_{x \to \infty}\,{1 \over x\,-\,3} \, = \, 12 \cdot \lim_{x \to \infty}\,{1 \over x} \, = \, 12 \cdot 0 \, = \, 0 \]
\[ \lim_{x \to \infty}\,{12 \over x\,-\,3} \, = \, 12 \cdot \lim_{x \to \infty}\,{1 \over x\,-\,3} \, = \, 12 \cdot \lim_{x \to \infty}\,{1 \over x} \, = \, 12 \cdot 0 \, = \, 0 \]